Hitunglah jumlah Network dan Host yang akan terbentuk dari alamat IP Address dibawah ini :
1. 192.168.10.1/30
2. 172.168.10.1/16
3. 172.168.10/22
4. 10.168.5.1/8
5. 10.168.5.1/17
Jawaban
1.
Netmask = 255.255.255.252
In binary = 11111111. 11111111. 11111111.11111100
Used to calculate = 11111100
Network = 2^n
= 2^6
= 64 Network
Host = 2^h-2
= 2^2-2
= 2 Host
2.
Netmask = 255.255.0.0
In Binary = 11111111.11111111.00000000.00000000
Used to calculate = 00000000.00000000
Network = 2^n
= 2^0
= 1 Network
Host = 2^h-2
= 2^16-2
= 65534 Host
3.
Netmask : 255.255.252.0
In Binary : 11111111.11111111.11111100.00000000
Used to calculate = 11111100.00000000
Network = 2^n
= 2^6
= 64 Network
Host = 2^h-2
= 2^10-2
= 1022 Host
4.
Netmask : 255.0.0.0
In Binary : 11111111.00000000.00000000.00000000
Used to calculate = 00000000.00000000.00000000
Network = 2^n
= 2^0
= 1 Network
Host = 2^h-2
= 2^24-2
= 167772614 Host
5.
Netmask : 255.255.128.0
In Binary : 11111111.11111111.10000000.00000000
Used to calculate = 11111111.10000000.00000000
Network = 2^n
= 2^9
= 512 Network
Host = 2^h-2
= 2^15-2
= 32766 Host
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